If seven equal-width panels have a combined width of 31 1/2 FT, what is the width of one panel?

Prepare for the NCCR Boilermaker Test. Study with flashcards and multiple choice questions, each question includes hints and explanations. Get ready for your exam!

Multiple Choice

If seven equal-width panels have a combined width of 31 1/2 FT, what is the width of one panel?

Explanation:
When panels are the same width, the total width is seven times the width of one panel, so you divide the total by seven. 31 1/2 FT divided by 7 equals 4 1/2 FT for each panel. This checks out because 4 1/2 FT times seven equals 31 1/2 FT. The other options don’t fit because they would produce totals of 28 FT, 35 FT, or 26 1/4 FT when multiplied by seven.

When panels are the same width, the total width is seven times the width of one panel, so you divide the total by seven. 31 1/2 FT divided by 7 equals 4 1/2 FT for each panel. This checks out because 4 1/2 FT times seven equals 31 1/2 FT. The other options don’t fit because they would produce totals of 28 FT, 35 FT, or 26 1/4 FT when multiplied by seven.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy